C – For Loop Logical Programs

C program to display Multiplication table for given number

#include<stdio.h> int main() {             int n, i;             printf(“Enter table number : “);             scanf(“%d”, &n);             for(i=1 ; i<=10 ; i++)             {                         printf(“%d x %d = %d \n”, n, i, n*i);             }                       return 0; }

C Program to display Sum of First N numbers

int main() {             int n, i, sum=0;             printf(“Enter n value : “);             scanf(“%d”, &n);             for(i=1 ; i<=n ; i++){                         sum = sum+i;             }                       printf(“Sum of first %d numbers is : %d \n”, n, sum);             return 0; }

C Program to display Factorial of Given Number

int main() {             int n, i, fact=1;             printf(“Enter n value : “);             scanf(“%d”, &n);             for(i=1 ; i<=n ; i++){                         fact = fact*i;             }                       printf(“Factorial of %d is : %d \n”, n, fact);             return 0; }

C Program to display Even numbers from 1 to 10

int main() {             int i;             for(i=1 ; i<=10 ; i++){                         if(i%2==0)                                     printf(“%d is even \n”, i);             }                       return 0; }

C Program to display sum of even numbers from 1 to 10

int main() {             int i, sum=0;             for(i=1 ; i<=10 ; i++){                         if(i%2==0)                                     sum = sum+i;             }                       printf(“Sum is : %d \n”, sum); }

C program to display factors of given number

int main() {             int i, n;             printf(“Enter n value : “);             scanf(“%d”, &n);             for(i=1 ; i<=n ; i++){                         if(n%i==0)                                     printf(“%d is a factor for %d \n”, i, n);             }                       return 0; }

C program to count the factors of given number

int main() {             int i, n, count=0;             printf(“Enter n value : “);             scanf(“%d”, &n);             for(i=1 ; i<=n ; i++){                         if(n%i==0)                                     count++;             }                       printf(“Number of Factors for %d is %d \n”, n, count);             return 0; }

C program to check the input number is prime or not

Prime Number: The Number which is having 2 Factors

int main() {             int i, n, count=0;             printf(“Enter n value : “);             scanf(“%d”, &n);             for(i=1 ; i<=n ; i++){                         if(n%i==0)                                     count++;             }                       if(count==2)                         printf(“%d is Prime number \n”, n);             else                              printf(“%d is not Prime number \n”, n);             return 0; }

C program to find the sum of factors for input number

int main() {             int i, n, sum=0;             printf(“Enter n value : “);             scanf(“%d”, &n);             for(i=1 ; i<=n ; i++){                         if(n%i==0)                                     sum=sum+i;             }                       printf(“Sum of factors of %d is %d \n”, n, sum);             return 0; }

Perfect Number Program: Sum of factors except itself is equals to the same number.

int main() {             int i, n, sum=0;             printf(“Enter n value : “);             scanf(“%d”, &n);             for(i=1 ; i<n ; i++){                         if(n%i==0)                                     sum=sum+i;             }                       if(n==sum)                         printf(“%d is Perfect number \n”, n);             else                         printf(“%d is not a perfect number \n”, n);             return 0; }

Fibonacci series: The series in which sum of 2 consecutive numbers will be the next number

Series: 0, 1, 1, 2, 3, 5, 8, 13, 21,…

int main() {             int i, n, a=0, b=1, c;             printf(“Enter limit : “);             scanf(“%d”, &n);             for(i=1 ; i<=n ; i++){                         printf(“%d  “, a);                         c = a+b ;                         a = b ;                         b = c ;             }                       return 0; }