Java – Check the first element Even or not
class Code { public static void main(String[] args) { int[] arr = {4, 2, 8, 9, 1, 6, 7, 5}; int first = arr[0]; if(first%2==0) System.out.println(“First element is Even”); else System.out.println(“First element is not Even”); } } |
Java – Check the sum of first and last elements is equals to 10 or not
class Code { public static void main(String[] args) { int[] arr = {4, 2, 8, 9, 1, 6, 7, 5}; int first = arr[0]; int last = arr[arr.length-1]; if(first+last==10) System.out.println(“Equals”); else System.out.println(“Not Equals”); } } |
Java – Program to check first and last elements of Array are same or not
class Code { public static void main(String[] args) { int[] arr = {4, 2, 8, 9, 1, 6, 7, 5}; if(arr[0]==arr[arr.length-1]) System.out.println(“Same”); else System.out.println(“Not Same”); } } |
Java – Program to Check the length of array is even or not
class Code { public static void main(String[] args) { int[] arr = {4, 2, 8, 9, 1, 6, 7, 5}; if(arr.length%2==0) System.out.println(“Even length array”); else System.out.println(“Not an Even length array”); } } |
Java – Check the last element of array is even or not
class Code { public static void main(String[] args) { int[] arr = {4, 2, 8, 9, 1, 6, 7, 5}; int n = arr.length; if(arr[n-1]%2==0) System.out.println(“Last element of Array is Even”); else System.out.println(“Last element of array is not even”); } } |
Java – Program to Check the length of array is prime or not
- Prime Number : A number which is having 2 factors
- First we need to find the length of array into variable n
- Count the factors of n value
- If the count is 2, then it is prime number
class Code { public static void main(String[] args) { int[] arr = {4, 2, 8, 9, 1, 6, 7}; int n = arr.length; int count=0; for (int i=1 ; i<=n ; i++) { if(n%i==0) count++; } if(count==2) System.out.println(“Array length is prime”); else System.out.println(“Array length is not prime”); } } |
Java – Check the first element of array is perfect number or not
- Perfect Number : Sum of factors except itself is equals to Perfect number
- Example : n=6 -> factors = 1, 2, 3, 6 -> 1+2+3 = 6
class Code { public static void main(String[] args) { int[] arr = {6, 2, 8, 9, 1, 6, 7, 5}; int n = arr[0]; int sum=0; for (int i=1 ; i<n ; i++){ if(n%i==0) sum = sum+i; } if(sum==n) System.out.println(“First element is Perfect Number”); else System.out.println(“First element is Not perfect Number”); } } |
Java – Print the factorial for first element in array
class Code { public static void main(String[] args) { int[] arr = {6, 2, 8, 9, 1, 6, 7, 5}; int n = arr[0]; int fact=1; for (int i=1 ; i<=n ; i++) { fact = fact*i; } System.out.println(“Factorial value is : ” + fact); } } |
Java – Display the multiplication table of last element in the array
class Code { public static void main(String[] args) { int[] arr = {6, 2, 8, 9, 1, 6, 7, 5}; int n = arr[arr.length-1]; for (int i=1 ; i<=10 ; i++) { System.out.println(n + ” x ” + i + ” = ” + (n*i)); } } } |